Question

Y=3x-5/(x^2+7) derivar ayudemen

Answer 1

$y= \frac{3x-5}{ x^{2}+7 }$
utilizando la regla de la Diferenciación
$(\frac{f}{g})'= \frac{f.g'-f'.g}{g^{2} }$ 
$y'= \frac{ \frac{d}{dx}(3x-5)( x^{2}+7)-(3x-5) \frac{d}{dx}( x^{2}-7)}{(x^{2}+7)^{2} }$
$y'= \frac{(3-0)( x^{2} +7)-(3x-5)(2x+0)}{(x^{2}+7)^{2} }$
$y'= \frac{3( x^{2} +7)-(3x-5)(2x)}{( x^{2} +7)^{2} }$
$y'= \frac{3 x^{2} +21-6x^{2}+10x }{( x^{2} +7)^{2} }$
$y'= \frac{-3 x^{2} +10x+21}{( x^{2}+7)^{2} }$   R//