Question

geente por favor ayudeneme

Answer 1

Respuesta:

$lim_{x > 3}( \frac{ \sqrt{x { }^{2 } - 2x + 6} - \sqrt{x {}^{2} + 2x - 6} }{x {}^{2} { - 4x + 3}^{} } ) \\ lim_{x > 3}( \frac{ \sqrt{x { }^{2 } - 2x + 6} - \sqrt{x {}^{2} + 2x - 6} }{x {}^{2} { - 4x + 3}^{} } x \frac{ \sqrt{x ^{2} - 2x - 6} - \sqrt{ \times ^{2} + 2x - 6} }{ \sqrt{x {}^{2} - 2x + 6 } - \sqrt{x {}^{2} +2x - 6 } }) \\ lim_{x > 3}( \frac{( \sqrt{ {}x^{2} - 2x + 6 } - \sqrt{x {}^{2} + 2x - 6 }) \times ( \sqrt{x {}^{2} - 2x + 6} - \sqrt{x {}^{2} + 2x - 6 } }{(x {}^{2} - 4 + 3)( \sqrt{x {}^{2} + 2x - 6 } + \sqrt{x {}^{2} - 2x + 6 }) } \\ lim_{x > 3}( \frac{x {}^{2} - 2x + 6(x {}^{2} + 2x - 6) }{(x {}^{2} - x - 3x + 3) \times ( \sqrt{x {}^{2} - 2x + 6 } + \sqrt{x {}^{2} + 2 x - 6) } } \\ lim_{x > 3}( \frac{ x {}^{2} - 2x + 6 - x { }^{2} - 2x + 6 }{(x \times (x - 1) - 3((x - 1)) \times ( \sqrt{x {}^{2} \times - 2x + 6 } + \sqrt{x {}^{2} + 2x - 6 }) } \\ lim_{x > 3}( \frac{ - 4x + 12}{(x - 1)(x - 3)( \sqrt{x {}^{2} - 2x + 6 } + \sqrt{x {}^{2} + 2x - 6 }) } \\ lim_{x > 3}( \frac{ - 4(x - 3)}{(x - 1)(x - 3)( \sqrt{ {}^{2} - 2x + 6 } + \sqrt{x {}^{2} + 2x - 6 }) } \\ lim_{x > 3}( \frac{ - 4}{(x - 1)( \sqrt{x {}^{2} - 2x + 6 } + \sqrt{x {}^{2} + 2x - 6} ) } \\ \frac{ - 4}{(3 - 1)( \sqrt{3 {}^{2} - 2 \times 3 + 6} + \sqrt{ {3}^{2} + 2 \times 3 - 6 } } \\ - \frac{1}{3}$