Question

35-(8-2)*1+(5*4)-12/6

Answer 1

$35-(8-2)*1+(5*4)- \frac{12}{6}= \qquad resolvemos \ la \ fracci\'on \\ \\ 35-(8-2)*1+(5*4)- 2=\qquad resolvemos \ los \ par\'entesis \\ \\ 35-(6)*1+(20)- 2= \\ \\ 35-6+20- 2= \qquad juntamos \ los \ positivos \ y \ los \ negativos\\ \\ (35+20) -(6+2)= 55-8= \boxed{47}$

Espero que te sirva, salu2!!!!