Question

Un gas ocupa 0,8m³ a 305 K y 1,82x10⁶ Pa. -Calcula a que presión estarà sometido si doblamos el volumen y mantenemos la temperatura constante.

Answer 1

Ley  de los gases ideales

P x V = n x R x T

R = 8.3144 (Pa x m³ / K mol)
v = 0.8 m³
T = 305 K (constante)
Pa = 1.82 x 10⁶

1. calcular moles    

n =      1.82 x 10⁶ Pa  x  0.8 m³
     `````````````````````````````````````````````
        8.3144 (Pa x m³/mol K) x 305 K

n = 574.15 mol

2. calcular el volumen y como se duplica el volumen = 2 (0.8 m³) = 1.6 m³

P = 574.15 moles x 8.3144 Pa x 305 K
      ````````````````````````````````````````````````
                         1.6 m³

P = 909988.99 Pa