Determina el porcentaje de carbono presente en los siguientes compuestos:
a) propano, C3H8
b) acido formico, COOH
c) dioxido de carbono, CO2
d) Monoxido de carbono, CO
e) acetileno, C2H2
Respuestas
Respuesta dada por:
152
a) C3H8
Mm
C: 3 x 12 = 36 g/mol
H: 8 x 1 = 8 g/mol
``````````````````````````````
Mm = 44 g/mol
% C
44 g ----- 100 %
36 g ----- x
x = 81.81 % C
b. H-COOH
Mm
C: 1 x 12 = 12 g/mol
H: 2 x 1 = 2 g/mol
O: 2 x 16 = 32 g/mol
``````````````````````````````
Mm = 46 g/mol
% Carbono
46 g ---- 100 %
12 g ---- x
x = 26.07 % C
c. CO2
C: 1 x 12 = 12 g/mol
O: 2 x 16 = 32 g/mol
````````````````````````````
Mm = 44 g/mol
%C
44 g ---- 100 %
12 g ---- x
x = 27.27 % C
d. CO
C: 1 x 12 = 12 g/mol
O: 1 x 16 = 16 g/mol
````````````````````````````
Mm = 28 g/mol
%C
28 g ---- 100 %
12 g ---- x
x = 42.86 % C
e. C2H2
C: 2 x 12 = 24 g/mol
H: 2 x 1 = 2 g/mol
````````````````````````````
Mm = 26 g/mol
%C
26 g ---- 100 %
24 g ---- x
x = 92.30 % C
Mm
C: 3 x 12 = 36 g/mol
H: 8 x 1 = 8 g/mol
``````````````````````````````
Mm = 44 g/mol
% C
44 g ----- 100 %
36 g ----- x
x = 81.81 % C
b. H-COOH
Mm
C: 1 x 12 = 12 g/mol
H: 2 x 1 = 2 g/mol
O: 2 x 16 = 32 g/mol
``````````````````````````````
Mm = 46 g/mol
% Carbono
46 g ---- 100 %
12 g ---- x
x = 26.07 % C
c. CO2
C: 1 x 12 = 12 g/mol
O: 2 x 16 = 32 g/mol
````````````````````````````
Mm = 44 g/mol
%C
44 g ---- 100 %
12 g ---- x
x = 27.27 % C
d. CO
C: 1 x 12 = 12 g/mol
O: 1 x 16 = 16 g/mol
````````````````````````````
Mm = 28 g/mol
%C
28 g ---- 100 %
12 g ---- x
x = 42.86 % C
e. C2H2
C: 2 x 12 = 24 g/mol
H: 2 x 1 = 2 g/mol
````````````````````````````
Mm = 26 g/mol
%C
26 g ---- 100 %
24 g ---- x
x = 92.30 % C
Preguntas similares
hace 6 años
hace 6 años
hace 9 años
hace 9 años
hace 9 años