Question

Resuelve los binomios al cuadrado
a) (4x - 5y)²
b) (3x + 2y)²
c) (2x + 3y)²
d) ( -12v +7z )²
e)(1/8a -3/4b)²
f) (4/5j -7/8a)²
ayudemen

Answer 1

16x^2-40xy+25y^2
4x^2+12xy+4x^2
9x^2+12xy+4x^2
24y^2+168yz+49z^2
1/64 a^2- 6/32ab+9/16bc^2

Answer 2

(a + b)² = a² + 2ab + b²

Si el binomio es de la forma (a - b), el cuadrado es:

(a - b)² = a² - 2ab + b²

a) (4x - 5y)²

(4x - 5y)² = (4x)² - 2(4x)(5y) + (5y)² = 16x² - 40xy + 25y²

b) (3x + 2y)²

(3x + 2y)² = (3x)² + 2(3x)(2y) + (2y)² = 9x² + 12xy + 4y²

c) (2x + 3y)²

(2x + 3y)² = (2x)² + 2(2x)(3y) + (3y)² = 4x² + 12xy + 9y²

d) ( -12v + 7z )²

(-12v + 7z)² = (7z - 12v)² = (7z)² - 2(7z)(12v) + (12v)² = 49z² - 168zv + 144v²

e)(1/8a - 3/4b)²

(1/8a - 3/4b)² = (1/8a)² - 2(1/8a)(3/4b) + (3/4b)² =

= (1/8)² a² - (2 x 1 x 3)/(8 x 4) ab + (3/4)² b² = 1/64 a² - 6/32 ab + 9/16 b²

f) (4/5j -7/8a)²

(4/5j - 7/8a)² = (4/5)² j² - 2(4/5)(7/8) ja + (7/8)² a² =

= (4²/5²) j² - (2 x 4 x 7) / (5 x 8) ja + (7²/8²) a² =

= 16/25 j² - 56/40 ja + 49/64 a²

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