Question

x elevado 2 - 8 x +16 = 0

Answer 1

$x^{2} -8x+16=0 \\ (x-4)(x-4)=0 \\ (x-4)^{2} =0 \\ \sqrt{(x-4)^{2}} = \sqrt{0} \\ x-4=0 \\ x=4$

:)