Question

cuantas moleculas presentan 15g de HCL (acido clorhidrico )

Answer 1

n=  m/Mm

Mm HCl = 36.5 g/mol

n = 15 g / 36.5 g/mol = 0.4109 mol

          1 mol -------- 6.022 x 10²³ moléculas

0.4109 mol --------   x

X = 2.47 x 10²³ moléculas