Question

la suma de tres numeros pares consecutivos es 30. Halla el mayor

Answer 1

x+1+x+2+x+3 = 30
3x + 6 = 30
3x =24
x = 8
8+1 = 9
8 +2 = 10
8+3 = 11 es el mayor
9+10+11=30
otro
x+2+x+1+x = 30
3x + 3 =30
3x = 27
x = 9
9+1 =10
9+2 =11
9+3 = 12 es la mayor
10+11+12 = 30
otro
x+1+x+x-1 = 30
3x = 30
x = 10
10+1 = 11 es la mayor
10-1 = 9
9+10+11 = 30
otro
x+x-1+x-2 = 30
3x -3 = 30
3x = 33
x = 11
11-1 = 10 es la mayor
11-2 = 9
11+10+9 = 30
y la ultima
x-1+x-2+x-3 = 30
3x-6 = 30
3x = 36
x = 12
12-1 = 11 es la mayor
12-2 = 10
12-3 = 9
11+10+9 = 30
hay 5 formas de resolver esta ecuacion