Question

las medidas de un triangulo rectangulo son a y b y su hipotenusa es h encuentre los valores de las funciones trigonometricas del angulo mas pequeño que conforma el triangulo
a) a=3 , b=7
b) a=2, b=9
c) a=7, h=15
d) a=17, b=5 e
e) a=18, h=22,5

Answer 1

El lado faltante lo sacas con Pitagoras

a)

h^2 = 9+49

h = raiz de 58 = 7.615

sen = 3/7.615

cos = 7/7.615

tan = 3/7

cot = 7/3

sec = 7.615/7

csc = 7.615/3

=====

b)

h^2 = 4+81

h = raiz de 85 = 9.21

sen = 2/9.21

cos = 9/9.21

tan = 2/9

cot = 9/2

sec = 9.21/9

csc = 9.21/2

====================

b^2 = 225 - 49

b = raiz de 176 = 13.266

sen = 7/15

cos = 13.266/15

tan = 7/13.266

cot = 13.266/7

sec = 15/13.266

csc = 15/7

===============

d)

h^2 = 289+25

h = raiz de 314

h = 17.72

sen = 17/17.72

cos = 5/17.72

tan = 17/5

cot = 5/17

sec = 17.72/5

csc = 17.72/17

==================

b^2 = 506.25 - 324

b = raiz de 182.25

b = 13.5

sen = 18/22.5

cos = 13.5/22.5

tan = 18/13.5

cot = 13.5/18

sec = 22.5/13.5

csc = 22.5/18

Answer 2

Lo resuelves con pitagoras: cateto a=√(hipotenusa)^2-(cateto b)^2 Cateto b=√(hipotenusa)^2-(cateto a)^2 Hipotenusa=√(cateto a)^2+(cateto b)^2 Entonces: a) h=√58 b) h=√85 c) b=4√11 d) h=21,77 e) b=27/2