Question

The width of a rectangular field is 60% of its length. How big is the field, if the owner occupied 280 meters of cyclonic fence to fence it?

Answer 1

First: 60% = 60/100 = 0.6

If the width is 60% of this length:

x = 0.6y                ec. 1
2x + 2y = 280        ec. 2

replacing ec. 1 on ec. 2:

2*(0.6y) + 2y = 280

1.2y + 2y = 280

3.2y = 280

y = 280/3.2

y = 87.5


The length is 87.5m


On the ec. 1:


x = 0.6y

x = 0.6*87.5

x = 52.5

The width is 52.5m


Now the area of the field is:


A = L*W

A = 87.5 * 52.5
A = 4593.75

The field area is 4593.75 m²

Saludos...