Question

2(x^2 -3x)=6(x-1)-8$\neq$

Answer 1

Respuesta:

$2(x^2-3x)=6(x-1)-8\\2x^2-6x=6x-6-8\\2x^2-12x+14=0\\x^2-6x+7=0\\\\x_1=\frac{6+\sqrt{36-28} }{2}=3+\sqrt{2}\\x_2= 3-\sqrt{2}$

Saludos!!