Question

plis ayudeme le daré de todo​

Answer 1

Recuerda que:

${x}^{ - y} = \frac{1}{ {x}^{y} }$

Voy a convertir a N y P en fraccion:

$N = 0.4 \\ N = \frac{4}{10} \\ N = \frac{2}{5}$

...

$P = 0. \frac{}{4} \\ P = \frac{4}{9}$

...

Solo reemplaza las letras con sus valores.

a)

$= {( - \frac{ 1}{3}) }^{ - 2} \times \sqrt{ \frac{4}{9} } \\ = {( - 3)}^{2} \times \sqrt{ \frac{ {2}^{2} }{ { 3}^{2} } } \\ = 9 \times \frac{2}{3} \\ = 6$

b)

$= { (\frac{2}{5} )}^{ - 1} \div \sqrt[3]{ \frac{4}{9} - \frac{4}{27} } \\ = \frac{5}{2} \div \sqrt[3]{ \frac{12}{27} - \frac{4}{27} } \\ = \frac{5}{2} \div \sqrt[3]{ \frac{8}{27} } \\ = \frac{5}{2} \div \sqrt[3]{ \frac{ {2}^{3} }{ {3}^{3} } } \\ = \frac{5}{2} \div \frac{2}{3} \\ = \frac{5}{2} \times \frac{3}{2} \\ = \frac{15}{4}$

c)

$= \sqrt{ - ( - \frac{1}{3} ) \div \frac{4}{27} } + \frac{2}{5} \times {( \frac{1}{3}) }^{ - 1} \\ = \sqrt{ \frac{1}{3} \times \frac{27}{4} } + \frac{2}{5} \times 3 \\ = \sqrt{ \frac{9}{4} } + \frac{6}{5} \\ = \sqrt{ \frac{ {3}^{2} }{ {2}^{2} } } + \frac{6}{5} \\ = \frac{3}{2} + \frac{6}{5} \\ = \frac{27}{10}$