Question

simplifica los radicales y resuelve las operaciones
a.$\sqrt{12} -2 \sqrt{27} -3 \sqrt{48} +2 \sqrt{75} +3 \sqrt{108}$

Answer 1

= $\sqrt{ 2^{2}3$ -  $2$ $\sqrt{ 3^{2}.3$ -$3$$\sqrt{ 2^{4}.3$ +$2$$\sqrt{ 5^{2}. 3$$+3 \sqrt{ 2^{2}. 3^{2}.3 }$

= 2$\sqrt{3}$$-2.3$$\sqrt{3}$ -$3. 2^{2} \sqrt{3} +2.5 \sqrt{3} +3.2.3 \sqrt{3}$

= $(2-6-12+10+18) \sqrt{3}$

=$12 \sqrt{3}$