Question

${(3x)}^{2} = {(x + 1)}^{2} + {(3x + 1)}^{2}$
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Answer 1

Respuesta:

x1 = - 0.2583 ^ x2 = - 7. 7416

Explicación paso a paso:

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${(3x)}^{2} = {(x + 1)}^{2} + {(3x + 1)}^{2} \\ 9 {x}^{2} = ({x}^{2} + 2x + 1) + (9 {x}^{2} + 6x + 1) \\ 0= {x}^{2} + 2x + 9 {x}^{2} + 6x - 9 {x}^{2} + 2$

$0= {x}^{2} + 8x + 2 \\ 0 = {x}^{2} + 8x + 2 + {4}^{2} - {4}^{2} \\ 0 = ({x}^{2} + 8x + {4}^{2} ) - {4}^{2} + 2 \\ 16 - 2 = {(x + 4)}^{2} \\ 14 = {(x + 4)}^{2}$

$\sqrt{14} = x + 4 \\ \sqrt{14} - 4 = x$

$x1 = + \sqrt{14} - 4 \\ x1 = - 0.2583$

$x2 = - \sqrt{14} - 4 \\ x2 = - 7.7416$