Question

$(0.8 \times \frac{27}{8} \times \frac{1}{3} ) - ( \sqrt{0.04} + \sqrt{0.36 {)}^{2} }$
​alguien me ayuda a resolverlo? es para hoy

Answer 1

Respuesta:

$\frac{17}{50}$

Explicación paso a paso:

$(0.8\times\frac{27}{8}\times\frac{1}{3})-(\sqrt{0.04}+\sqrt{(0.36)^{2}}\\0.8=\frac{8}{10}=\frac{4}{5}\\0.36=\frac{36}{100}=\frac{9}{25}\\0.04=\frac{4}{100}=\frac{1}{25}\\\\(\frac{8}{10}\times\frac{27}{8}\times\frac{1}{3})-\left(\sqrt{\frac{4}{100}}+\sqrt{(\frac{36}{100})^{2}}\right)=(\frac{4}{5}\times\frac{27}{8}\times\frac{1}{3})=\frac{(4)(27)(1)}{(5)(8)(3)}=\frac{108}{120}=\frac{9}{10}\\\\\sqrt{\frac{4}{100}}=\frac{\sqrt{4}}{\sqrt{100}}=\frac{2}{10}=\frac{1}{5}\\\\\sqrt{(\frac{36}{100})^{2}}=\frac{36}{100}=\frac{9}{25}\\\\\texttt{Reuniendo todo nos queda:}\\(\frac{9}{10})-(\frac{1}{5}+\frac{9}{25})=(\frac{9}{10})-(\frac{5+9}{25})=(\frac{9}{10})-(\frac{14}{25})=\frac{9}{10}-\frac{14}{25}=\frac{45-28}{50}=\frac{17}{50}$

Saludos