Question

Quien me ayuda en esto por favor?

Answer 1

SOLUCIÓN

♛ HØlα!! ✌

Para desarrollar solo reemplazamos

                        $1-\dfrac{b}{1-b}=\dfrac{(1-b)-b}{1-b}\\\\\\1-\dfrac{b}{1-b}=\dfrac{1-2b}{1-b}, \:\:\:pero\:\:\:b=1-\dfrac{1}{a}\\\\\\1-\dfrac{b}{1-b}=\dfrac{1-2(1-\frac{1}{a})}{1-(1-\frac{1}{a})}\\\\\\1-\dfrac{b}{1-b}=\dfrac{1-2(\frac{a-1}{a})}{1-(\frac{a-1}{a})}\\\\\\1-\dfrac{b}{1-b}=\dfrac{1-(\frac{2a-2}{a})}{1-(\frac{a-1}{a})}\\\\\\1-\dfrac{b}{1-b}=\dfrac{\frac{a-(2a-2)}{a}}{\frac{a-(a-1)}{a}}\\\\\\1-\dfrac{b}{1-b}=\dfrac{\frac{a-2a+2}{a}}{\frac{a-a+1}{a}}$

                        $1-\dfrac{b}{1-b}=\dfrac{\frac{-a+2}{a}}{\frac{1}{a}}\\\\\\\boxed{\boxed{\boldsymbol{1-\dfrac{b}{1-b}=-a+2}}}$

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