Question

método de sustitución 2×+y=10 5×-3y=3​

Answer 1

SOLUCIÓN

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                       $Despejaremos\:"x"\:de\:la\:primera\:ecuaci\'on\\\\2x+y=10\\\\\\2x=10-y\\\\\\x=\dfrac{10-y}{2}\\\\\\Reemplazamos\:x\:en\:la\:segunda\:ecuaci\'on\\\\\\5x-3y=3\\\\\\(5)\left(\dfrac{10-y}{2}\right)-3y=3\\\\\\\dfrac{(5)(10-y)+[(2)(-3y)]}{2}=3\\\\\\(50-5y)+(-6y)=(3)(2)\\\\\\50-11y=6\\\\\\-11y=-44\\\\\\y=\dfrac{-44}{-11}\\\\\\\boxed{\boldsymbol{y=4}}$

                      $Reemplazamos\:"y"\:en\:"x"\\\\\\x=\dfrac{10-y}{2}\\\\\\x=\dfrac{10-(4)}{2}\\\\\\x=\dfrac{10-4}{2}\\\\\\x=\dfrac{6}{2}\\\\\\\boxed{\boldsymbol{x=3}}$