Question

Si: a # b = a² - b calcula ( 3 #2) + ( 2 # 1 ) .

Answer 1

3 # 2 = 3² - 2 = 9 - 2 = 7

2 # 1 = 2² - 1 = 4 - 1 = 3

(3 # 2) + (2 # 1)

7 + 3

10

Answer 2

1) remplazando

a es 3 y b es 2

${3}^{2} - 2 = 7$

2)reemplazando

a es 2 y b es 1

${2}^{2} - 1 = 3$

Rpta: 7 + 3 = 10