Question

ayuden porfavor amigos

Answer 1

$\frac{2}{x+3}= \frac{4}{x^{2} -9} \\\\\frac{2}{x+3}(x+3)= \frac{4}{x^{2} -9} (x+3)\\\\2=\frac{4(x+3)}{x^{2} -9} \\\\2(x^{2}-9)=\frac{4(x+3)}{x^{2} -9}(x^{2} -9)\\\\2x^{2} -18=4x+12\\\\2x^{2} -4x-30=0\\\\x^{2} -2x-15=0\\\\(x-5)(x+3)=0\\\\x-5=0\\\\x=5\\\\x+3=0\\\\x=-3$