Question

Si se disuelven 25 g de metanol en 50 g de h2O La fraccion de molar demetanol es ?

Answer 1

soluto = 25 g Metanol Mm CH3OH = 32 g/mol

solvente = 50 g H2O Mm H2O = 18 g/mol

1. calcular moles de soluto y moles de solvente

n = masa/Mm

nCH3OH = 25 g / 32 g/mol = 0.78 mol

nH2O = 50 g / 18 g/mol = 2.77 mol

2. calcular moles totales

n totales = n soluto + n solvente

n totales = 0.78 mol + 2.77 mol

n totales = 3.55

3. calcular fracción molar del soluti

X soluto = n soluto/n totales

X soluto = 0.78 mol / 3.55 mol = 0.22

4. calcular fracción molar del solvente

Xsvte = n svte /n totales

Xsvte = 2.77 mol / 3.55 mol = 0.78

5. Xsto + Ssvte = 1

0.22 + 0.78 = 1

Answer 2

Respuesta:

soluto = 25 g Metanol Mm CH3OH = 32 g/mol

solvente = 50 g H2O Mm H2O = 18 g/mol

1. calcular moles de soluto y moles de solvente

n = masa/Mm

nCH3OH = 25 g / 32 g/mol = 0.78 mol

nH2O = 50 g / 18 g/mol = 2.77 mol

2. calcular moles totales

n totales = n soluto + n solvente

n totales = 0.78 mol + 2.77 mol

n totales = 3.55

3. calcular fracción molar del soluti

X soluto = n soluto/n totales

X soluto = 0.78 mol / 3.55 mol = 0.22

4. calcular fracción molar del solvente

Xsvte = n svte /n totales

Xsvte = 2.77 mol / 3.55 mol = 0.78

5. Xsto + Ssvte = 1

0.22 + 0.78 = 1

Explicación: