Question

General de la circunferencia C(2, -3/2), r=2 √10

Answer 1

(x$(x-h)^{2}+(y-k)^{2}=R^{2}$

(x$(x-2)^{2}+(y+\frac{3}{2})^{2}=(2\sqrt{10})^{2}$

x^2-4x+4+y^2+3y+$\frac{9}{4}$ =40

x^2+y^2-4x+3y-$\frac{-135}{4}$ =0