Question

ayudenme a calcular : 1/2 √3xy entre 3/4 √x ????

Answer 1

$= \frac{1}{2} \sqrt{3xy} \div \frac{3}{4} \sqrt{x} \\ = \frac{\frac{1}{2} \sqrt{3xy}}{\frac{3}{4} \sqrt{x} } \\ = \frac{1 \times 4 \times \sqrt{3xy} }{2 \times 3 \times \sqrt{x} } \\ = \frac{2 \sqrt{3y} }{3} \\ = \frac{2 \sqrt{y} }{ \sqrt{ 3} }$