Question

Log (2x + 1) – Log (2x - 1) = 2Log3 – 3Log2

Answer 1

$log( \frac{2x + 1}{2x - 1} ) = log(9) - log(8) \\ log( \frac{2x + 1}{2x - 1} ) = log( \frac{9}{8} ) \\ \frac{2x + 1}{2x - 1} = \frac{9}{8} \\ 16x + 8 = 18x - 9 \\ 8 + 9 = 2x \\ \frac{17}{2} = x$

Answer 2

Otro aporte... utilizando las propiedades de los logaritmos.