Question

Log 2 = m , Log 3 = n , x = Log 36.

Answer 1

Propiedades a usar
$log( {x}^{n} ) = n log(x) \\ log(a \times b) = log(a) + log(b)$
Entonces
$x = log(36) \\ x = log( {6}^{2} ) \\ x = 2 log(6) \\ x = 2( log(2 \times 3) ) \\ x = 2( log(2) + log(3) ) \\ x = 2(m + n)$

Answer 2

Aplicando propiedades operacionales de otencis

36 = 2^2x3^2

log36 = x

= log(2^2x3^2)

= log2^2 + log3^2

= 2log2 + 2log3

= 2(m) + 2(n)

x = 2(m + n) respuesta