Question

me ayudan a despejar esta variable

$2xy = 8x - 3$

${y}^{2} - 5 = 4x - 1$

Answer 1

2xy-8x =-3
x(2y-1)=-3
X=-3/2y-1

y^2 - 5=4x - 1
y^2 +6 =4x
y^2+6/4= x
X=y^2+6/4