Question

Cuantos gramos de Argón (Ar) ocuparía un volumen de 25 L a condiciones normales?

Answer 1

Mm Ar = 39.94 g/mol

1. calcular moles de argón

       1 mol ---- 22.4 L
           x    ----  25 L

 X = 1 mol x 25 L
      ``````````````````
            22.4 L

x = 1.116 mol

2. calcular gramos de argón

n = m/Mm

m = 1.11 mol x 39.94 g/mol

m = 44.33 g de Ar

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CN

T = 273 K
P = 1 tm
n = ?
R = 0.0821 (l atm/mol K)
V = 25 L

Utilizar la  fórmula de la ley de los gases

P x V = n x R x T

n =            1 atm  x  25 L
      ````````````````````````````````````````
      0.0821 (L atm/mol K) x 273 K

n = 1.11 mol

calcular g de Ar

n = m/Mm

m = 1.115 mol x 39.34 g/mol

m = 44.33 g