Question

Por favor ayudarme!
Sobre estás preguntas

Answer 1

1) 4 +1/2
$4 + \frac{1}{2} \\ = \frac{8 + 1}{2} = \frac{9}{2}$
2)
$- \frac{3}{2} + \frac{1}{3} \\ \frac{ - 3 \times 3 + 1 \times 2}{6} = \frac{ - 9 + 2}{6} = - \frac{7}{6}$
3)
$- \frac{4}{5} - ( - 3) - \frac{2}{3} \\ = - \frac{4}{5} + 3 - \frac{2}{3} \\ = \frac{ - 4 \times 3 + 3 \times 15 - 2 \times 5}{15} \\ = \frac{ - 12 + 45 - 10}{15} = \frac{23}{15}$
4)
$3 \sqrt{16} - 2 \sqrt{25} \\ 3 \times 4 - 2 \times 5 \\ 12 - 10 = 2$

5)
$- 4 \sqrt{5} + \sqrt{5} = - 3 \sqrt{5}$
6) Tienes que ocupar pitagoras:

${c}^{2} = {1}^{2} + {2}^{2} \\ {c}^{2} = 1 + 4 \\ {c}^{2} = 5 \\ c = \sqrt{5}$
${b}^{2} + {1}^{2} = { \sqrt{2} }^{2} \\ {b}^{2} + 1 = 2 \\ {b}^{2} = 2 - 1 \\ {b}^{2} = 1 \\ b = 1$
8) 3x - 5=2x+1
3x-2x =1+5
x=6