Question

como calcular la diagonal menor de un rombo si el area es 2400 m cuadrados y la diagonal mayor mide 80 m

Answer 1

$Area \ del \ rombo\ = \frac{Diagonal \ mayor * digonal \ menor}{2} \\ \\ 2400\ m^2 = \frac{80m*diagonal \ menor}{2} \\ \\ 2400 \ m^2 * 2 = 80m * \ diagonal \ menor \\ \\ \frac{4800 \ m^2}{80\m} = diagonal \ menor \\ \\ 60\ m = diagonal \ menor$

Espero que te sirva, salu2!!!!