Question

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Answer 1

1.        2NO + Cl2 ⇄ 2NOCl

Kp =   [NOCl]²
       ````````````````
        [NO]² [Cl₂]


[NOCl]² = Kp x [NO]² [Cl₂]

[NOCl] = √Kp x [NO]² [Cl₂]

[NOCl] = √ 52 x ( 0.095)² x (0.171)

 [NOCl] = √ 0.0803  = 0.28  mol/L

2.     PCl3 + Cl2 ⇄ PCl5

Kp = [PCl5] / [PCl3][Cl2]

Kp = ( 1.30) / (0.124)(0.157)

Kp = 66.78

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