Question

Csc x sec x - tan x

Answer 1

${\csc x.\sec x - \tan x=}\\\\{\dfrac{1}{\sin x}.\dfrac{1}{\cos x}-\dfrac{\sin x}{\cos x}=}\\\\\\{\dfrac{1-\sin^2 x}{\sin x.\cos x}=}\\\\\\{\dfrac{\cos^2x}{\sin x.\cos x}=}\\\\\\{\dfrac{\cos x}{\sin x}=}\\\\\\{\boxed{\boxed{\cot x}}}$



Salu2. :)