Question

3x²-5x-2=0
(formula general y con comprobacion)

Answer 1

3x²-5x-2=0

a=3
b=-5
c=-2

x₁=$\frac{-b+ \sqrt{b ^{2}-4ac } }{2a}= \frac{5+ \sqrt{(-5) ^{2}-4(3)(-2) } }{2(3)}= \frac{5+ \sqrt{25+24} }{6}= \frac{5+ \sqrt{49} }{6}= \frac{5+7}{6}= \frac{12}{3}$=2

x₂=$\frac{5-7}{6}= \frac{-2}{6}= -\frac{1}{3}$

Comprobación.

3x²-5x-2=0
3(-1/3)²-5(-1/3)-2=0
1/3+5/3-2=0
0=0


3x²-5x-2=0
3(2)²-5(2)-2=0
12-10-2=0
0=0

Saludos!!

Answer 2

Explicación paso a paso:

3x²-5x-2=0

a=3

b=-5

c=-2

x₁=\frac{-b+ \sqrt{b ^{2}-4ac } }{2a}= \frac{5+ \sqrt{(-5) ^{2}-4(3)(-2) } }{2(3)}= \frac{5+ \sqrt{25+24} }{6}= \frac{5+ \sqrt{49} }{6}= \frac{5+7}{6}= \frac{12}{3}

2a

−b+

b

2

−4ac

=

2(3)

5+

(−5)

2

−4(3)(−2)

=

6

5+

25+24

=

6

5+

49

=

6

5+7

=

3

12

=2

x₂=\frac{5-7}{6}= \frac{-2}{6}= -\frac{1}{3}

6

5−7

=

6

−2

=−

3

1

Comprobación.

3x²-5x-2=0

3(-1/3)²-5(-1/3)-2=0

1/3+5/3-2=0

0=0

3x²-5x-2=0

3(2)²-5(2)-2=0

12-10-2=0

0=0