Question

Si A y B son dos angulos suplementarios, donde A= 8(2x-3) y B= 10(x+3.5)

Answer 1

8(2x-3) + 10(x+3.5) = 180
16x-24 + 10x+35 = 180
16x+10x = 180+24-35
26x = 169
x = 169/26
x = 6.5

A = 8(2x-3)
A = 8*((2*6.5)-3)
A = 8*(13-3)
A = 8*10
A = 80°

B = 10(x+3.5)
B = 10(6.5+3.5)
B = 10*10
B = 100°

Comprobación:
100+80 = 180

Los ángulos miden:
A: 80°
B: 100°