Question

Que volumen ocuparan 10 gramos de oxigeno gaseoso a una temperatura de 22 °C y una presion de 740 torr?
Recuerde que= 1 atm = 760 torr y K=°C+273

Answer 1

Ley de los gases Ideales

V x P = n x R x T

Mm O2 = 32 g/mol
n = masa/Mm
n = 10 g / 32 g/mol
n = 0.313 moles de O2

P = 760 Torr

     1 atm --- 760 torr
         x    ---  740 torr

          x = 0.97 atm

T = 22 ºC + 273 = 295 K
R = 0.082 (L atm / mol K)

Calcular  volumen

V = 0.313 mol x 0.082 (L atm/mol K) x 295 K
       ````````````````````````````````````````````````````````
                              0.97 atm

V = 7.805 L