Question

procedimiento 74%de carbono, 8.65 % de hidrogeno y 17.35% de nitrogeno. su masa molecular es de 262g/mol.

Answer 1

1. calcular moles

C: 74 g / 12 g/mol = 6.167 mol
H: 8.65 g/ 1 g/mol = 8.65 mol
N: 17.35 g/14 g/mol = 1.239 mol

2. dividir entre el menor de los resultados

C: 6.167 mol / 1.239 mol = 5
H: 8.65 mol / 1.239 mol = 7
N: 1.239 mol / 1.239 mol =1

3. FE: C5H7N

4. Calcula la Mm FE

C. 5 x 12 = 60 g/mol
H: 7 x 1 = 7 g/mol
N: 1 x 14 = 14 g/mol
```````````````````````````````
       Mm = 81 g/mol

5. calcular n = Mm compuesto /Mm FE

n = 162 g/mol
      ``````````````
       81 g/mol

n = 2

6. FM: (C5H7N)2 = C10H14N2

NOTA: revisar Mm de la nicotina es 162 g/mol y no 262 g/mol