Question

 ECUACIONES CUADRATICAS RESOLVER:
x^{2} -10x+25=0
 x^{2} -6x=16
(x-5)^{2} =144
 x^{2} +10x=36x

PORFAVOR

Answer 1

a) x^{2} -10x+25=0
(x-5)(x-5)=0
xsub1=5 y xsub2=5

b) x^{2} -6x=16
x^{2} -6x-16=0
(x-8)(x+2)=0
xsub1=8 y xsub2=-2

c)(x-5)^{2}=144
$\sqrt{ (x-5)^{2} }$ = $\sqrt{144}$
x-5=12
x=17

d)x^{2} +10x=36x
x^{2} +10x-36x=0
x^{2}-26x=0
x(x-26)=0
xsub1=0 y xsub2=26

suerte!! espero haberte ayudado ;)