Question

cuantos gramos de Al2(SO4)3 se producen si reaccionan 7.5 moles de H2SO

Answer 1

        2Al(OH)3 + 3 H2SO4 → Al2(SO4)3 + 6H2O

Mm Al2(SO4)3 = 342.15 g/mol

g = 7.5 mol H2SO4 x 1 mol Al2(SO4)3  x  342.15 g Al2(SO4)3
                                  ````````````````````````   `````````````````````````````        
                                     3 mol H2SO4         1 mol Al2(SO4)2

g = 855.38 g de Al2(SO4)3