Respuestas
Respuesta dada por:
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1. (a + 3)³= a³ + 3(a)²(3) + 3(a)(3)² + (3)³= 27 + 9a² + 27a + 27
2. (p – q)³ = p³ – 3(p)²(q) + 3(p)(q)² – q³= p³ – 3p²q + 3pq² - q³
3. (x + 2)³ = x³ + 3(x)²(2) + 3(x)(2)² + 2³= x³ + 6x² + 12x + 8
4. (a – 3)³ = a³ + 3(a)²(3) + 3(a)(3)²+ (3)³= a³ + 9a² + 27a + 27
5. (t + 4)³ = t³ + 3(t)²(4) + 3(t)(4)² + (4)³ == t³ + 3(t)²(4) + 3(t)(4)² + (4)³= t³ + 12t² + 48t + 64
6. (2 – a)³ = 2³ – 3(2)²(a) + 3(2)(a)² – a³= 8 – 12a + 6a² - a³
7. (2a – b)³ = (2a)³ -3(2a)²(b)+3(2a)(b)²- b³ =8a³ – 3(4a²)b + 6ab² – b³= 8a³ – 12a²b + 6ab² – b³
8. (3a - 5b)³ = (3a)³-3(3a)²(5b)+3(3a)(5b)²-(5b)³= 27a³ - 135a²b + 225ab² - 125b³
9. (2x + 3y)³=(2x)³+3(2x)²(3y)+3(2x)(3y)²+(3y)³ = 8x³ + 36 x²y + 54xy² + 27y³
10. (1 – 3y)³ = (1)³ – 3(1)²(3y)+3(1)(3y)²- (3y)³ = 1 – 9y + 27y² - 27y³
2. (p – q)³ = p³ – 3(p)²(q) + 3(p)(q)² – q³= p³ – 3p²q + 3pq² - q³
3. (x + 2)³ = x³ + 3(x)²(2) + 3(x)(2)² + 2³= x³ + 6x² + 12x + 8
4. (a – 3)³ = a³ + 3(a)²(3) + 3(a)(3)²+ (3)³= a³ + 9a² + 27a + 27
5. (t + 4)³ = t³ + 3(t)²(4) + 3(t)(4)² + (4)³ == t³ + 3(t)²(4) + 3(t)(4)² + (4)³= t³ + 12t² + 48t + 64
6. (2 – a)³ = 2³ – 3(2)²(a) + 3(2)(a)² – a³= 8 – 12a + 6a² - a³
7. (2a – b)³ = (2a)³ -3(2a)²(b)+3(2a)(b)²- b³ =8a³ – 3(4a²)b + 6ab² – b³= 8a³ – 12a²b + 6ab² – b³
8. (3a - 5b)³ = (3a)³-3(3a)²(5b)+3(3a)(5b)²-(5b)³= 27a³ - 135a²b + 225ab² - 125b³
9. (2x + 3y)³=(2x)³+3(2x)²(3y)+3(2x)(3y)²+(3y)³ = 8x³ + 36 x²y + 54xy² + 27y³
10. (1 – 3y)³ = (1)³ – 3(1)²(3y)+3(1)(3y)²- (3y)³ = 1 – 9y + 27y² - 27y³
Jhonaycker:
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