Question

Cuantos gramos de oxido férrico se puede producir a partir de 12,80 gramos de oxigeno que reaccionan con hierro solido?

Answer 1

                   4 Fe +   3 O2 → 2Fe2O

Mm Fe2O3 = 159.68 g/mol

             O2 = 32 g/mo

g Fe2O3 = 12.80 g O2 x 1 mol O2  x  2 mol Fe2O3  x  159.68 g Fe2O3

                                        ````````````     ``````````````````     ````````````````````````

                                          32 g O2        3 mol O2             1 mol Fe2O3

g Fe2O3 = 42.58