Question

expresar como potencia de exponente racional. √99 √365 √44 √75 √3 √18 √243

Answer 1

$\sqrt{99}= \sqrt{3^2.11}= \sqrt{3^2} \sqrt{11}= 3 \sqrt{11}\to 3.(11)^{ \frac{1}{2}} \\ \\ \sqrt{365}=(365) ^{ \frac{1}{2}} \\ \\ \sqrt{44}= \sqrt{2^2.11}= \sqrt{2^2}. \sqrt{11}= 2. \sqrt{11}\to 2.(11)^{ \frac{1}{2}} \\ \\ \sqrt{75}= \sqrt{3.5^2}= \sqrt{3}. \sqrt{5^2}=5. \sqrt{3}\to 5.(3)^{ \frac{1}{2}} \\ \\ \sqrt{3}= (3)^{ \frac{1}{2}} \\ \\ \sqrt{18}= \sqrt{2.3^2}= \sqrt{2}. \sqrt{3^2}= 3. \sqrt{2}\to 3.(2)^{ \frac{1}{2}}$

$\sqrt{243}= \sqrt{3^4.3}= \sqrt{3^4} \sqrt{3}=3^2. \sqrt{3} \to 9.(3)^{ \frac{1}{2}}$

Espero que te sirva, salu2!!!!