x+2/4 + y-1/2 = 7/2 x-5/2 - x-3/3 = 1/6 metodo de igualación
Anónimo:
¡Hola!, para forma un sistema de ecuaciones tiene que haber dos variables, y en la segunda ecuación solamente veo una, la cual es "x", tal ves sea un error de tipeo , es : x-5/2 - "y"-3/3 = 1/6
Respuestas
Respuesta dada por:
4
X+2/4 + y-1/2 = 7/2 x-5/2 - y -3/3 = 1/6 metodo de igualación
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![\textbf{M\'etodo de Igualaci\'on.}\\ \\ Vamos\ a\ despejar\ "x". \\ \\ Ecua(1) : \\ \\ x + \dfrac{2}{4}+y -\dfrac{1}{2} = \dfrac{7}{2} \\ \\ El\ mcm\ de\ los\ denominadores\ es\ "4". \\ \\ x + \dfrac{2}{4}+y -\dfrac{1*2}{2*2} = \dfrac{7*2}{2*2} \\ \\ \\ x + \not{\dfrac{2}{4}}+y -\not{\dfrac{2}{4}} = \dfrac{14}{4} \\ \\ \\ x = \dfrac{14:2}{4:2}-y \\ \\ \\ \boxed{x = \frac{7}{2}-y } \textbf{M\'etodo de Igualaci\'on.}\\ \\ Vamos\ a\ despejar\ "x". \\ \\ Ecua(1) : \\ \\ x + \dfrac{2}{4}+y -\dfrac{1}{2} = \dfrac{7}{2} \\ \\ El\ mcm\ de\ los\ denominadores\ es\ "4". \\ \\ x + \dfrac{2}{4}+y -\dfrac{1*2}{2*2} = \dfrac{7*2}{2*2} \\ \\ \\ x + \not{\dfrac{2}{4}}+y -\not{\dfrac{2}{4}} = \dfrac{14}{4} \\ \\ \\ x = \dfrac{14:2}{4:2}-y \\ \\ \\ \boxed{x = \frac{7}{2}-y }](https://tex.z-dn.net/?f=%5Ctextbf%7BM%5C%27etodo+de+Igualaci%5C%27on.%7D%5C%5C+%5C%5C+Vamos%5C+a%5C+despejar%5C+%22x%22.+%5C%5C+%5C%5C+Ecua%281%29+%3A+%5C%5C+%5C%5C+x+%2B+%5Cdfrac%7B2%7D%7B4%7D%2By+-%5Cdfrac%7B1%7D%7B2%7D+%3D+%5Cdfrac%7B7%7D%7B2%7D+%5C%5C+%5C%5C+El%5C+mcm%5C+de%5C+los%5C+denominadores%5C+es%5C+%224%22.+%5C%5C+%5C%5C+x+%2B+%5Cdfrac%7B2%7D%7B4%7D%2By+-%5Cdfrac%7B1%2A2%7D%7B2%2A2%7D+%3D+%5Cdfrac%7B7%2A2%7D%7B2%2A2%7D+%5C%5C+%5C%5C+%5C%5C+x+%2B+%5Cnot%7B%5Cdfrac%7B2%7D%7B4%7D%7D%2By+-%5Cnot%7B%5Cdfrac%7B2%7D%7B4%7D%7D+%3D+%5Cdfrac%7B14%7D%7B4%7D+%5C%5C+%5C%5C+%5C%5C++x+%3D+%5Cdfrac%7B14%3A2%7D%7B4%3A2%7D-y+%5C%5C+%5C%5C+%5C%5C+%5Cboxed%7Bx+%3D+%5Cfrac%7B7%7D%7B2%7D-y+%7D)
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![Ecua(2) : \\ \\ Despejamos\ "x". \\ \\ x- \dfrac{5}{2}-y-\dfrac{3}{3} = \dfrac{1}{6} \\ \\ \\ x- \dfrac{5*3}{2*3}-y-\dfrac{3*2}{3*2} = \dfrac{1}{6} \\ \\ \\ x- \dfrac{15}{6}-y-\dfrac{6}{6} = \dfrac{1}{6} \\ \\ \\ x = \dfrac{1}{6}+ \dfrac{15}{6}+ \dfrac{6}{6}+y \\ \\ \\ x = \dfrac{22:2}{6:2}+y \\ \\ \\ \boxed{\boxed{x= \frac{11}{3}+y }} Ecua(2) : \\ \\ Despejamos\ "x". \\ \\ x- \dfrac{5}{2}-y-\dfrac{3}{3} = \dfrac{1}{6} \\ \\ \\ x- \dfrac{5*3}{2*3}-y-\dfrac{3*2}{3*2} = \dfrac{1}{6} \\ \\ \\ x- \dfrac{15}{6}-y-\dfrac{6}{6} = \dfrac{1}{6} \\ \\ \\ x = \dfrac{1}{6}+ \dfrac{15}{6}+ \dfrac{6}{6}+y \\ \\ \\ x = \dfrac{22:2}{6:2}+y \\ \\ \\ \boxed{\boxed{x= \frac{11}{3}+y }}](https://tex.z-dn.net/?f=Ecua%282%29+%3A+%5C%5C+%5C%5C+Despejamos%5C+%22x%22.+%5C%5C+%5C%5C+x-+%5Cdfrac%7B5%7D%7B2%7D-y-%5Cdfrac%7B3%7D%7B3%7D+%3D+%5Cdfrac%7B1%7D%7B6%7D+%5C%5C+%5C%5C+%5C%5C+x-+%5Cdfrac%7B5%2A3%7D%7B2%2A3%7D-y-%5Cdfrac%7B3%2A2%7D%7B3%2A2%7D+%3D+%5Cdfrac%7B1%7D%7B6%7D+%5C%5C+%5C%5C+%5C%5C+x-+%5Cdfrac%7B15%7D%7B6%7D-y-%5Cdfrac%7B6%7D%7B6%7D+%3D+%5Cdfrac%7B1%7D%7B6%7D+%5C%5C+%5C%5C+%5C%5C+x+%3D+%5Cdfrac%7B1%7D%7B6%7D%2B+%5Cdfrac%7B15%7D%7B6%7D%2B+%5Cdfrac%7B6%7D%7B6%7D%2By+%5C%5C+%5C%5C+%5C%5C+x+%3D++%5Cdfrac%7B22%3A2%7D%7B6%3A2%7D%2By+%5C%5C+%5C%5C+%5C%5C+%5Cboxed%7B%5Cboxed%7Bx%3D+%5Cfrac%7B11%7D%7B3%7D%2By+%7D%7D+)
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![Ahora\ igualamos. \\ \\ Ecua(1) = Ecua(2) . Ahora\ igualamos. \\ \\ Ecua(1) = Ecua(2) .](https://tex.z-dn.net/?f=Ahora%5C+igualamos.+%5C%5C+%5C%5C+Ecua%281%29+%3D+Ecua%282%29+.)
![\dfrac{7}{2} -y = \dfrac{22}{6} + y \\ \\ \\ \dfrac{21}{6} - \dfrac{22}{6} = 2y \\ \\ \\ - \dfrac{1}{6} = 2y \\ \\ \\ \boxed{\boxed{- \frac{1}{12} =y}} \dfrac{7}{2} -y = \dfrac{22}{6} + y \\ \\ \\ \dfrac{21}{6} - \dfrac{22}{6} = 2y \\ \\ \\ - \dfrac{1}{6} = 2y \\ \\ \\ \boxed{\boxed{- \frac{1}{12} =y}}](https://tex.z-dn.net/?f=+%5Cdfrac%7B7%7D%7B2%7D+-y+%3D++%5Cdfrac%7B22%7D%7B6%7D+%2B+y++%5C%5C+%5C%5C+%5C%5C+++%5Cdfrac%7B21%7D%7B6%7D+-++%5Cdfrac%7B22%7D%7B6%7D+%3D+2y+%5C%5C+%5C%5C+%5C%5C+-++%5Cdfrac%7B1%7D%7B6%7D+%3D+2y+%5C%5C+%5C%5C+%5C%5C++%5Cboxed%7B%5Cboxed%7B-+%5Cfrac%7B1%7D%7B12%7D+%3Dy%7D%7D++)
Ahora reemplazamos en cualquiera de las ecuaciones en "y", para hallar el valor de "x".
Reemplazamos en la Ecua(2).
![x = \dfrac{22}{6} + y \\ \\ \\ x = \dfrac{44}{12} - \dfrac{1}{12} \\ \\ \\ \boxed{\boxed{x= \frac{43}{12} }} x = \dfrac{22}{6} + y \\ \\ \\ x = \dfrac{44}{12} - \dfrac{1}{12} \\ \\ \\ \boxed{\boxed{x= \frac{43}{12} }}](https://tex.z-dn.net/?f=x+%3D++%5Cdfrac%7B22%7D%7B6%7D+%2B+y+%5C%5C+%5C%5C+%5C%5C+x+%3D++%5Cdfrac%7B44%7D%7B12%7D+-++%5Cdfrac%7B1%7D%7B12%7D+%5C%5C+%5C%5C+%5C%5C+%5Cboxed%7B%5Cboxed%7Bx%3D+%5Cfrac%7B43%7D%7B12%7D+%7D%7D++)
Ahora reemplazamos en cualquiera de las ecuaciones en "y", para hallar el valor de "x".
Reemplazamos en la Ecua(2).
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