Question

OFREZCO 35 PTS CON PROCEDIMIENTO
MEGA URGE PARA HOY!!

Resuelve las siguientes ecuaciones
2x = 4x - 8

3(x + 2) + 2 = 2x

2(-3 - x) + 2 = - ( - 2x + 4) + 2x

(1/x) = 2/(x+3)

2x^{2} + 3x = 0

6x^{2} - 36 = 0

x^{2} + 4x - 12 = 0

x^{2} - 2x - 8 = 0

Answer 1

ö2x = 4x - 8
8= 4x-2x
8=2x
4=x

3(x + 2) + 2 = 2x
3x+6+2=2x
3x-2x=-6-2
x= -8

2(3 - x) + 2 = - ( - 2x + 4) + 2x
6-2x+2= 2x-4+2x
6+2+4=4x+2x
12=6x
2=x

(1/x) = 2/(x+3)
1(x+3)= 2x
x+3=2x
3=2x-x
3=x

2x^{2} + 3x = 0
x( 2x+3)=0

x=0

2x+3=0
2x=-3
x= -3/2

6x^{2} - 36 = 0
6x^2=36
x^2=6
x= + o - raiz de 6

x^{2} + 4x - 12 = 0
x ................. 6
x .................-2

x+6=0
X=-6

X-2=0
x=2

x^{2} - 2x - 8 = 0
x...............-4
x............... 2

x-4=0
x=4

x+2=0
x=-2