Question

la distancia entre los puntos A(-3,-4) Y B(1,-1) ES:

Answer 1

${d=\sqrt{(x_2+x_1)^2+(y_2-y_1)^2}}\\\\{d=\sqrt{(-3-1)^2+(-4+1)^2}}\\\\{d=\sqrt{(-4)^2+(-3)^2}}\\\\{d=\sqrt{16+9}}\\\\{d=\sqrt{25}}\\\\{\boxed{d=5}}$


Salu2.!! :)
Wellington

Answer 2

¡Hola!
Vamos a calcular la distancia entre dos puntos usando el Teorema de Pitágoras:

$d^2_{AB} = [x_B - x_A]^2 + [y_B - y_A]^2$

$\sqrt{d^2_{AB} } = \sqrt{[x_B - x_A]^2 + [y_B - y_A]^2}$

$d_{AB} = \sqrt{[x_B - x_A]^2 + [y_B - y_A]^2}$

Datos:

$x_B = 1$

$x_A = - 3$

$y_B = - 4$

$y_A = - 1$

Resolviendo:

* distancia de A hasta B

$d_{AB} = \sqrt{[x_B - x_A]^2 + [y_B - y_A]^2}$

$d_{AB} = \sqrt{[1 - (-3)]^2 + [-4 - (-1)]^2}$

$d_{AB} = \sqrt{[1 + 3]^2 + [-4 + 1]^2}$

$d_{AB} = \sqrt{[4]^2 + [-3]^2}$

$d_{AB} = \sqrt{16 +9}$

$d_{AB} = \sqrt{25}$

$\boxed{\boxed{d_{AB} = 5}}\end{array}}\qquad\checkmark$