Question

Qué cantidad de solución (volumen) 2M (molar) se puede preparar con 800 g de HCl

Answer 1

1. calcular Mm HCl = 36.45 g/mol

2. calcular moles

mol HCl = 800 g HCl  x   1 mol HCl
                                      `````````````````
                                       36.45 g HCl

mol HCl = 21.947

3. calcular V(L) despejando de la fórmula M = mol soluto / V(L)

V(L) = 21.947 mol
         ``````````````````
           2 mol / L

V (L) = 10.97