Question

logaritmos log2 (x² + 1) - log2 x = 1

Answer 1

${log_2(x^2+1)-log_2(x)=1}\\\\{log_2(x^2+1)-log_2(x)=log_2(2)}\\\\{log_2\left( \frac{x^2+1}{x} \right)=log_2(2)}\\\\{ \frac{x^2+1}{x} =2}\\\\{x^2+1=2x}\\\\{x^2-2x+1=0}\\\\{(x-1)^2=0}\\\\{x-1=0}\\\\{\boxed{x=1}}$

Salu2.!! :)
Wellington