Question

Log3(2x-1)-log3(5x+2)=log3(x-2)-2

Answer 1

log3 (2x-1) - log3 (5x+2) = log3 (x-2)-2 

log3((2x-1)/(5x+2)) = log3(x-2) – log3(3^2) 

log3((2x-1)/(5x+2)) = log3((x-2)/9) 

(2x-1)/(5x+2) = (x-2)/9 

18x -9 = 5x^2-8x-4 

5x^2-26x +5=0 

x = (26±raiz(676-100))/10 = (26±24)/10 

x = 5 ó x = 1/5