Question

(y+2)(y-1)+(-y)²=(2y-1)(y+2)-4

Answer 1

(y+2)(y-1)+(-y)²=(2y-1)(y+2)-4
y²-y+2y-2+y²=2y²+4y-y-2-4
2y²+y-2=2y²+3y-6
2y²+y-2-2y²-3y+6=0
-2y+4=0
-2y=-4
y=-4/-2
y=2