Question

!!AYUDA POR FAVOR!!
LA PRIMERA ECUACIÓN ME TIENE QUE DAR 18/13 Y LA SEGUNDA 22/9, PERO NO SÉ CÓMO SEGUIR RESOLVIENDO.

Answer 1

$\textbf{Resolvemos :} \\ \\ \dfrac{5x-4}{4} = \dfrac{2}{3}\left(\dfrac{x}{4}- \dfrac{1}{2}\right) + \dfrac{5}{6} \\ \\ \dfrac{5x-4}{4} = \dfrac{2x}{12} - \dfrac{2}{6}+\dfrac{5}{6} \\ \\ \dfrac{5x-4}{4} = \dfrac{2x}{12}+ \dfrac{3*2}{6*2} \\ \\ \dfrac{5x-4}{\not{4}} = \dfrac{2x+6}{\not{12}} \\ \\ \dfrac{5x-4}{1} = \dfrac{2x+6}{3} \\ \\ 3(5x - 4) = 1(2x + 6) \\ \\ 15x - 12 = 2x + 6 \\ \\ 15x - 2x = 6 + 12 \\ \\ 13x = 18 \\ \\ \boxed{\boxed{ x=\frac{18}{13} }}$

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$\dfrac{3+x}{2} = 2(2 - x) + \dfrac{x}{4} - \sqrt[3]{-27} \\ \\ \dfrac{3+x}{2} = 4 - 2x + \dfrac{x}{4} - (-3) \\ \\ \dfrac{3+x}{2} = 7 + \dfrac{-8x+x}{4} \\ \\ \dfrac{3+x}{2} = 7 - \dfrac{7x}{4}\\ \\ \dfrac{3+x}{\not{2}} = \dfrac{28-7x}{\not{4}}\\ \\ 3 + x = \dfrac{28-7x}{2} \\ \\ 2(3 + x) = 28 - 7x \\ \\6 + 2x = 28 - 7x \\ \\ 2x +7x = 28 - 6\\ \\ 9x = 22 \\ \\ \boxed{\boxed{x= \frac{22}{9} }}$