Question

como resuelvo esta ecuacion
5logx-log32=logx/2

Answer 1

${5logx-log32=log(x/2)}\\\\{log(x)^5-log(32)=log(x/2)}\\\\{log{\left( \frac{x^5}{32} \right)=log\left( \frac{x}{2} \right)}}\\\\{ \frac{x^5}{32} = \frac{x}{2} }\\\\{ \frac{x^5}{x}= \frac{32}{2} }\\\\{x^4=16}\\\\{x= \sqrt[4]{16} }\\\\{x=2}\\\\{\text{salu2.!! :)}}$