Question

Ayuda!!! resolver completando cuadrados

Answer 1

${x^2-5x=14}\\{x^2-5x+....=14+.....}\\{x^2-5x+ \frac{25}{4} =14+ \frac{25}{4} }\\{(x- \frac{5}{2} )^2= \frac{81}{4}}\\{x- \frac{5}{2} = \sqrt{ \frac{81}{4} }} \\\\{x= \frac{9}{2} + \frac{5}{2} }\\{x= \frac{14}{2} }\\{x_1=7}\\\\{x=- \frac{9}{2} + \frac{5}{2} }\\{x= -\frac{4}{2} }\\{x_2=-2}$

Salu2.!! :)